10b^2-15b=25

Solution for 10b^2-15b=25 equation:

10b^2-15b=25

We move all terms to the left:

10b^2-15b-(25)=0

a = 10; b = -15; c = -25;
Δ = b2-4ac
Δ = -152-4·10·(-25)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-35}{2*10}=\frac{-20}{20}
=-1
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+35}{2*10}=\frac{50}{20}
=2+1/2
$